find the value of x for which 8x+4,6x-2and2x+7 are in ap
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Answered by
4
Heya !!!
AP = 8X + 4 , 6X -2 , and 2X + 7
Here,
First term ( A ) = 8X + 4
Second term ( A2 ) = 6X - 2
And,
Third term ( A3 ) = 2X + 7
Common Difference ( D ) = A2 - A1
=> ( 6X - 2 ) - ( 8X + 4 )
=> 6X - 2 - 8X - 4
=> -2X - 6
Also,
Common Difference ( D ) = A3 - A2
=> 2X + 7 - ( 6X - 2 )
=> 2X + 7 - 6X + 2
=> -4X + 9
As we know that,
Common Difference of an AP is always equal.
so,
A2 - A1 = A3 - A2
-2X - 6 = -4X + 9
-4X + 2X = -6 - 9
-2X = -15
X = 15/2
★ HOPE IT WILL HELP YOU ★
AP = 8X + 4 , 6X -2 , and 2X + 7
Here,
First term ( A ) = 8X + 4
Second term ( A2 ) = 6X - 2
And,
Third term ( A3 ) = 2X + 7
Common Difference ( D ) = A2 - A1
=> ( 6X - 2 ) - ( 8X + 4 )
=> 6X - 2 - 8X - 4
=> -2X - 6
Also,
Common Difference ( D ) = A3 - A2
=> 2X + 7 - ( 6X - 2 )
=> 2X + 7 - 6X + 2
=> -4X + 9
As we know that,
Common Difference of an AP is always equal.
so,
A2 - A1 = A3 - A2
-2X - 6 = -4X + 9
-4X + 2X = -6 - 9
-2X = -15
X = 15/2
★ HOPE IT WILL HELP YOU ★
VijayaLaxmiMehra1:
:-)
Answered by
4
Hey!!
AP = 8x + 4, 6x - 2 and 2x + 7
First term (A1) = 8x + 4
Second term ( A2 ) = 6x - 2
and
Third term ( A3 ) = 2x + 7
Common Difference ( D ) = A2 - A1
=> ( 6x - 2 ) - ( 8x + 4 )
=> 6x - 2 - 8x - 4
=> - 2x - 6
Common Difference ( D ) = A3 - A2
=> ( 2x + 7 ) - ( 6x - 2 )
=> 2x + 7 - 6x + 2
=> - 4x + 9
We know that,
Common Difference of AP is always equal
A2 - A1 = A3 - A2
=> - 2x - 6 = - 4x + 9
=> - 2x + 4x = 9 + 6
=> 2x = 15
=> x = 15 / 2
Hope it will helps you ✌
AP = 8x + 4, 6x - 2 and 2x + 7
First term (A1) = 8x + 4
Second term ( A2 ) = 6x - 2
and
Third term ( A3 ) = 2x + 7
Common Difference ( D ) = A2 - A1
=> ( 6x - 2 ) - ( 8x + 4 )
=> 6x - 2 - 8x - 4
=> - 2x - 6
Common Difference ( D ) = A3 - A2
=> ( 2x + 7 ) - ( 6x - 2 )
=> 2x + 7 - 6x + 2
=> - 4x + 9
We know that,
Common Difference of AP is always equal
A2 - A1 = A3 - A2
=> - 2x - 6 = - 4x + 9
=> - 2x + 4x = 9 + 6
=> 2x = 15
=> x = 15 / 2
Hope it will helps you ✌
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