Find the value of x for which 8x+7,6x-2,2x+7 are in AP
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Heya folk !!!
Here's the answer you are looking for
If these terms are in AP then their common difference would be same.
Let the common difference be d.
So,
3rd term - 2nd term = 2nd term - 1st term = d
Similarly,
For 8x+7, 6x-2, 2x+7
2x + 7 - (6x - 2) = 6x - 2 - ( 8x + 7) = d
2x + 7 - 6x + 2 = 6x - 2 - 8x - 7
-4x + 9 = -2x - 9
-4x + 2x = -9 - 9
-2x = -18
x = -18/(-2) = 9
So, x = 9
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
If these terms are in AP then their common difference would be same.
Let the common difference be d.
So,
3rd term - 2nd term = 2nd term - 1st term = d
Similarly,
For 8x+7, 6x-2, 2x+7
2x + 7 - (6x - 2) = 6x - 2 - ( 8x + 7) = d
2x + 7 - 6x + 2 = 6x - 2 - 8x - 7
-4x + 9 = -2x - 9
-4x + 2x = -9 - 9
-2x = -18
x = -18/(-2) = 9
So, x = 9
★★ HOPE THAT HELPS ☺️ ★★
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