Question

find the value of x for which De is parallel to ab. ad is equals to 3 X + 19 this is equals to X + 3 be is equals to 3x+4 find ce​

Answer 1

by thale theorem

CD\AD=CE/BE

By cross multiplication ,we get

x=2

Answer 2

The length of CE is 2 units.

Step-by-step explanation:

Given information: DE║AB, AD=3x+19, CD=x+3, BE=3x+4 and CE=x.

We need to find the value of x.

Triangle Proportionality Theorem : According to this theorem if a line segment intersect two side of the triangle and parallel to third side of the triangle then it divides both sides proportionally.

Using Triangle Proportionality Theorem we get

$\dfrac{AD}{CD}=\dfrac{BE}{CE}$

$\dfrac{3x+19}{x+3}=\dfrac{3x+4}{x}$

On cross multiplication we get

$(3x+19)x=(3x+4)(x+3)$

$3x^2+19x=3x^2+9x+4x+12$

$19x=13x+12$

Subtract 13x from both sides.

$19x-13x=12$

$6x=12$

Divide both sides by 6.

$x=2$

Therefore, the length of CE is 2 units.

#Learn more

State the basic proportionality theorem.

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