Question

find the value of x , for which DE parallel to AB , DC =x+ 3 , AD=3x +19, BE =3x +14 , EC = x​

Answer 1

Hey mate here is ur answer!!

Answer:

As ABC is a triangle..

DE//AB

Step-by-step explanation:

Given..

DC = x+3

AD = 3x+19

BE = 3x-14

EC = x

By the Thales theorem or Basic Proportionality theorem..

• CE/EB = CD/DA
• x/3x-14 = x+4/3x+19

By cross multiplication..

• (x) (3x+19) = (x+4) (3x-14)
• 3x^2 + 19x = 3x^2 + 14x + 12x - 56

Taking the L.H.S to R.H.S

• 3x^2 + 26x - 56 - 3x^2 - 19x = 0
• 7x - 56 = 0
• 7x = 56
• x = 56/7
• x = 8

Therefore 'x' value is "8"..

Thank you for asking the question..

Hope it helps you..