Question

find the value of X for which PQ is parallel to RS in figure.
(a)3 (b)4 (c)5 (d)6​

Answer 1

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Answer 2

Answer:

(c) 5

Step-by-step explanation:

By BPT:

TR/PT = RS/PQ

TR/ (TR+PR) = RS/PQ

(OR)

(x-1)/ [(x-1) + (x+3)] = (x-3)/ (x+1)

(x-1)/ (2x+2) = (x-3)/ (x+1)

(x-1)/ 2(x+1) = (x-3)/ (x+1)

(x-1)(x+1) = (x-3)(x+1)2

x-1 = 2(x-3)

x-1 = 2x-6

x = 5

Hence Found

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