Find the value of x for which the angles ( 2x -5)° and ( x -10)° are the supplementary angles .
2 points
35
65
25
70
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2
Answer:
we know that sum of supplementary angles is equal to 180°
Then,
( 2x-5 )° +(x-10)°=180°
2x-5+x-10=180°
3x-15=180°
3x=180+15
3x=195
X=195/3=65
X=65°
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