Question

Find the Value of x for which the distance between the Points P (4,5) and Q (12,x) is 10 units

Answer 1

i think 11 is right answer

Answer 2

Answer:

The value of x is either 11 or -1.

Step-by-step explanation:

It is given that the distance between the Points P (4,5) and Q (12,x) is 10 units.

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$10=\sqrt{(12-4)^2+(x-5)^2}$

$100=64+(x-5)^2$

$36=(x-5)^2$

$\pm6=x-5$

$6=x-5$

$x=6+5=11$

$-6=x-5$

$x=-6+5=-1$

Therefore the value of x is either 11 or -1.