Find the value of x for which the distance between the points P (4,-5) Q(12,x) is 10 units
Answers
Answered by
20
1 or -11.
Use formula:
d^2 = (x1-x2)^2 + (y1-y2)^2.
100=64 + (-5-x)^2.
-x-5 = -6 or -x-5 = 6.
so x =1 or x= -11
Use formula:
d^2 = (x1-x2)^2 + (y1-y2)^2.
100=64 + (-5-x)^2.
-x-5 = -6 or -x-5 = 6.
so x =1 or x= -11
arshdeepkaur287:
Thanks
Answered by
15
i Think this could be answer the answer is in the attachment ⬆️⬆️ . but I am not sure about and if you think I had done any mistake please let me know it in comment
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i hope It will help you ✌❤
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