Question

find the value of x for which the distance between the points a(x,2) and B(9,8)is 10units

Answer 1

The value of X is 1unit.(or)17units.

Answer 2

The value of x is 1 and 17.

Step-by-step explanation:

Given : The distance between the points a(x,2) and B(9,8) is 10 units.

To find : The value of x ?

Solution :

The distance between two point is given by

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, $A(x_1,y_1)=(x,2),\ B(x_2,y_2)=(9,8)$

$10=\sqrt{(9-x)^2+(8-2)^2}$

Squaring both side,

$100=(81-18x+x^2)+(6)^2$

$100=x^2-18x+117$

$x^2-18x+17=0$

$x^2-17x-x+17=0$

$x(x-17)-1(x-17)=0$

$(x-17)(x-1)=0$

$x=17,1$

The value of x is 1 and 17.

#Learn more

Point p divides the line segment joining the point A(-1,3) and B(9,8) such that AP/PB=k/1 if p lies on the line x-y+2=0 find the value of k

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