Question

find the value of x for which the distance between the point p (2,-3) and Q (3,5) is 10 units






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Answer 1

AnswerSolution

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Given,

Distance between P and Q=10

⇒  

(x−2)  

2

+(5+3)  

2

 

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=10[ Using distance formula ]

⇒x  

2

−4x+68=100

⇒x  

2

−4x−32=0

⇒x  

2

−8x+4x−32=0

⇒(x−8)(x+4)=0

⇒x=8,−4

ALL THE NUMBER THAT ARE DOWN FRROM THE OTHER NUMBERS ARE POWER

Answer 2

Answer:

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Step-by-step explanation:

Given,

Distance between P and Q=10

(x−2) 2+(5+3) .

=10[ Using distance formula ]