Question

Find the value of x for which the distance between the point (3,-5) and (x,2) is 7 unit intext:zigya mbose

Answer 1

√({X2 - X1}² + {y2 - y1}²)=7
squaring on both the sides and putting the values of x1,y1,x2,y2
we get
(x-3)²+(2-(-5))²=49
x²+9-6x+49=49
x²-6x+9=0
by factorisation method
x²-3x-3x+9=0
X(x-3)-3(x-3)=0
(x-3)(x-3)=0
so X=3