find the value of x for which the distance between the point p(x, 3) and q(10,9) is 10 units
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hruthika25:
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Answer:
Step-by-step explanation:
√(x₂-x₁) + (y₂-y1) = 10
square on both side
(10-x)² + (9-3)² = 100
(10-x)² + 36 = 100
(10 -x )²= 100 - 36
(10 - x)² = 64
10 - x =√64
10 - x =8
x =2
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