find the value of x for which the distance between the two pointsp (2,-3) and Q(x,5) is 10 unit
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Using distance formula,
√(x-2)^2+(5+3)^2=10
Squaring on both sides
(x-2)^2+64=100
x^2+4-4x-36=0
x^2-4x-32=0
x^2+4x-8x-32=0
x(x+4)-8(x+4)=0
So, x=-4 or x=8
√(x-2)^2+(5+3)^2=10
Squaring on both sides
(x-2)^2+64=100
x^2+4-4x-36=0
x^2-4x-32=0
x^2+4x-8x-32=0
x(x+4)-8(x+4)=0
So, x=-4 or x=8
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