Question

find the value of x for which the distance is 4,5and 12,x is 10 units

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Answer 1

Answer:

D²=(x2-x1)² + (y2-y1)²

(10)²=(12-4)² + (x-5)²

100 = (8)²+x²+25-10x

100 = 64+25-10x+x²

100 = 89+x²-10x

x²-10x-100+89=0

x²-10x-11=0

x²-(11x-x)-11=0

x²-11x+x-11=0

x(x-11) + 1(x-11)=0

(x-11)(x+1)=0

x=11, x= -1

thus, x=11

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