Question

find the value of x for which the numbers (5x+2),(4x-1),and (x+2)are in A.P.​

Answer 1

Answer:

$x=3$

Step-by-step explanation:

$a1 = 5x+2, a2= 4x-1,a3=x+2\\for \:the \:terms\: to \:be\: in \:AP\\a2-a1 = a3-a2\\(4x-1) - (5x+2) = (x+2)- (4x-1)\\4x-1-5x-2 = x+2-4x+1\\2x = 6\\x = 3$

Answer 2

Answer:

This is your answer

you can check here