Find the value of x for which the numbersc(5x+2),(4x-1) and (x+2) are in A. P.
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soumyadip64:
hey why u had written 2(4x-1)
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Common difference cannot be changed. So common in 5x + 2 , 4x - 1 and x + 2 will be same.
Difference between ( x + 2 ) and ( 4x - 1 ) = x + 2 - ( 4x - 1 ) = x - 4x + 2 + 1 = - 3x + 3
Difference between 4x - 1 and 5x + 2 = 4x - 1 - ( 5x + 2 ) = 4x - 5x - 1 - 2 = - x - 3
As we know that they common difference will be same.
Difference between x + 2 and 4x - 1 =
Difference between 4x - 1 and 5x + 2
- 3x + 3 = - x - 3
3 + 3 = 3x - x
6 = 2x
3 = x
Therefore, value of x satisfying the equation is 3
Difference between ( x + 2 ) and ( 4x - 1 ) = x + 2 - ( 4x - 1 ) = x - 4x + 2 + 1 = - 3x + 3
Difference between 4x - 1 and 5x + 2 = 4x - 1 - ( 5x + 2 ) = 4x - 5x - 1 - 2 = - x - 3
As we know that they common difference will be same.
Difference between x + 2 and 4x - 1 =
Difference between 4x - 1 and 5x + 2
- 3x + 3 = - x - 3
3 + 3 = 3x - x
6 = 2x
3 = x
Therefore, value of x satisfying the equation is 3
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