Question

Find the value of x for which the points (7,-2),(5,1) and (3,k) are collinear?

Answer 1

Hello !!

For you know it, you can use the method of equality of slopes. See the resolution in the practice.

(yB - yA)/(xB - xA) = (yC - yB)/(xC - xB)

(1 - (-2))/(5 - 7) = (k - 1)/(3 - 5)

(1 + 2)/(5 - 7) = (k - 1)/(3 - 5)

(3)/(-2) = (k - 1)/(-2)

-2(k - 1) = 3(-2)

-2k + 2 = -6

-2k = -6 - 2

-2k = -8

k = (-8)/(-2)

k = 4

Final result : 4 is the solution for (k).

I hope I have collaborated !