Find the value of x for which the points (x,-1),(2,1)&(4,5) are collinear.
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Formula is x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
x(1-5)+2(5+1)+4(-1-1)=0
-4x + 12-8 = 0
-4x + 4 = 0
x = 1.
Hope this helps!
x(1-5)+2(5+1)+4(-1-1)=0
-4x + 12-8 = 0
-4x + 4 = 0
x = 1.
Hope this helps!
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