Question

Find the value of x for which the quadratic eq. 2-Kx+K=0 has equal root​

Answer 1

Answer:

we have given the question that equation 2x2+kx+k=0 has equal roots. So, we get two values of k k=0 and k=8 . Option D is the correct answer.

Answer 2

Step-by-step explanation:

$2 {x}^{2} - kx + k = 0$

Comparing it units

$a=2 , b = - k, c = k$

Roots are equal

${b}^{2} - 4ac = 0$

${( - k)}^{2} - 4(2)(k) = 0$

${k}^{2} - 4 \times 2 \times k = 0$

${k}^{2} - 8k = 0$

$k(k - 8) = 0$

$k = 0 \: \: or \: \: k - 8 = 0$

$k = 0 \: \: or \: \: k = 8$

$k =0, 8$

I hope it is helpful