find the value of x for which (x+1)^2 +(x^2+3x+2)^2 +(x^2+4+3)^2 =0
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(x+1)^2 + (x+1)^2 (x+2)^2 + (x+1)^2 (x+3)^2 = 0
x+1 = 0 ie., x = -1.
or
1 + (x+2)^2 + (x +3)^3 = 0
This is not possible as it is a sum of squares and so LHS >=1.
Answer: x = -1
x+1 = 0 ie., x = -1.
or
1 + (x+2)^2 + (x +3)^3 = 0
This is not possible as it is a sum of squares and so LHS >=1.
Answer: x = -1
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