Find the value of x for which x+2, 2x, 2x+3 are three consecutive terms of an AP
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Answered by
5
we know that If three numbers a, b, c are in AP, then
2b=a+c (AM)
So,
2 (2x)=(x+2)+(2x+3)
=) 4x=3x+5
=) x=5
if you have any other doubts don't hesitate to ask.
regards
nimit sharma
2b=a+c (AM)
So,
2 (2x)=(x+2)+(2x+3)
=) 4x=3x+5
=) x=5
if you have any other doubts don't hesitate to ask.
regards
nimit sharma
kpadmanabhannai:
Tq
Answered by
1
x+2,2x and 2x+3 are in AP. so, 2(2x)=(x+2)+(2x+3).
4x=x+2+2x+3
4x=3x+5
x=5
4x=x+2+2x+3
4x=3x+5
x=5
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