Math, asked by karmapelzang, 11 months ago

find the value of x for which x+9,x-6,4 are the first three terms of a GPand calculate the fourth term of progression..

Answers

Answered by brunoconti
0

Answer:

Step-by-step explanation:

x + 9 , x - 6 , 4 are in A.P., then

x + 9 + 4 = 2(x - 6)

x + 13 = 2x - 12

x = 25

the first Three terms are 34, 19 and 4. the fourth term is 4 - 15 = - 11.


karmapelzang: sorry how we get that 2
brunoconti: because if a , b , c are three consecutive terms of an A.P, then b- a = c - b which means that a + c = 2b
cmmanish473: Sorry, it its about GP
Answered by mkrishnan
4

they are in gp

(x-6)^2=4(x+9)

x^2 -12x+36=4x+36

x^2-16x=0

x(x-16)=0

x=0 and=16

if x=0

the gp is 9,-6,4 fourth term - 8/3

if x=16

the gp is 25,10,4 Fourth term 8/5

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