Question

find the value of ‘ x ' from figure​

Answer 1

Answer:

PR = 5

Step-by-step explanation:

ΔPQR is a right angles triangle

By Pythagoras theorem,

PQ² + QR² = PR²

let PR be x

(3)² + (4)² = x²

x = √((3)² + (4)²)

x = √(9 + 16)

x = √25

x = 25

PR = 5

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Answer 2

Answer:

PR= 5cm

Step-by-step explanation:

We know that Pythagoras theory applies on a right angled triangle.

So, According to Pythagoras theory;

$(Hypotenuse)^{2}=(Altitude)^{2}+(Base)^{2} \\\\According. to. figure, \\\\Altitude = 3cm\\Base=4cm\\So,\\(H)^{2}=3^{2}+4^{2} \\x^{2}=9+16\\x^{2}=25\\x=\sqrt{25} \\Therefore, x=5cm$