Question

find the value of x from the equation please​

Answer 1

hey mate :

given here:

3²[7^0+4^(2x)]=2313/256

=>3²[1+4^(2x)]=2313/256

=>3²+3²×4^(2x)=2313/256

=>9+9×4^(2x)=2313/256

=>9×4^(2x)= 2313/256 - 9

=>9×4^(2x)=(2313-2304)/256

=>9×4^(2x)= 9/256

=>4^(2x)= 1/256

=>4^(2x}= (1/4)^4

=>4^(2x)= 4^(-4)

=>2x= -4

=>x = -4 /2

=>x = -2

I hopes its helps u

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@Abhi.❤❤❤