Question

Find the value of x if [1x1][132][251][15 32][12x]=0

Answer 1

$\color{red}\huge{\underline{\underline{\mathfrak{Answer}}}}$

⠀⠀

(1×1)(132)(251)(1532)(12x)=0

(1)(132)(251)(1532)(12x)=0

x=$\frac{0}{1\times132\times251\times1532\times12}$

${\blue{\bold{\text{We know that}}}}$

${\pink{\text{When 0 is divided by any number we get 0 as result}}}$

Hence, x=0

$\rule{300}3$

Hope it helps.