Math, asked by nitinkarnwal521, 1 month ago

Find the value of x, if [2^2x-2 +10] ÷13 = 2.​

Answers

Answered by girda071974
4

Answer:

the value of x:

Step-by-step explanation:

[2^2x-2+10]÷13=2

[2^2x-2+10]=13*2

[2^2x-2+10]=26

2^2x-2=26-10

2^2x-2=16

2^2x-2=2^4

so on comparing both the sides base;

we get; 2x-2=4

2x=4+2

2x=6

x=3

I hope this will help you

Similar questions