Math, asked by nitinkarnwal521, 1 month ago

Find the value of x, if (2^2x-2 + 10)÷13 = 2.​

Answers

Answered by prafullamonapara4
0

Answer:

\textbf{To find:}To find:

\text{The value of x}The value of x

\textbf{Solution:}Solution:

\text{Consider,}Consider,

\dfrac{2^{2x-2}+10}{13}=2

13

2

2x−2

+10

=2

\implies\,2^{2x-2}+10=26⟹2

2x−2

+10=26

\implies\,2^{2x-2}=26-10⟹2

2x−2

=26−10

\implies\,2^{2x-2}=16⟹2

2x−2

=16

\implies\,2^{2x-2}=2^4⟹2

2x−2

=2

4

\text{Equating powers on bothsides, we get}Equating powers on bothsides, we get

2x-2=42x−2=4

2x=4+22x=4+2

2x=62x=6

\implies\boxed{\bf\,x=3}⟹

x=3

\therefore\textbf{The value of x is 3}∴The value of x is 3

\textbf{Find more:}Find more:

If 5^x-1 + 5^x+1=650 then find x

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