Math, asked by asgajinkar, 1 year ago

Find the value of x if 2^4×2^5=(2^5)^x

Answers

Answered by vivo1726
9

2^4 * 2^ 5 = 16 * 32 = 512

512 = (2^5)^x

512 = 32 x 2^x

512/32 = 2^x

16 = 2^x

2^4 = 16.....

x = 4......


asgajinkar: Ans.in the book is given 3
vivo1726: 2*2*2*2*2*2*2*2*2 = 512....= 2^9
vivo1726: follow me
Answered by gayatrikumari99sl
0

Answer:

\frac{9}{5}   is the required value of x.

Step-by-step explanation:

Explanation:

Given in the question, 2^4 . 2 ^5 = (2^5)^x

  • Exponents are simply added when multiplying two numbers or variables with the same base.
  • We multiply the bases and the same exponent when multiplying expressions with the same exponent but distinct bases.

Step 1:

We have, 2^4 . 2 ^5 = (2^5)^x

2^4 . 2^5 = 2^{5x}

Here we can see that base are same which is 2.

So, we take 2 as common and add the powers.

2^{4 +5} = 2^{5x}

2^9 = 2^{5x}

Now, we compare the powers

⇒ 9 = 5x

⇒ x = \frac{9}{5}

Final answer:

Hence, \frac{9}{5} is the required value of x.

#SPJ2

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