find the value of x,if 2 power x + 2 power (x+1) + 2 power (x+3) + 2 power (x+3) = 15*root32
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2^x+2^(x+1)+2^(x+2)+2^(x+3)=15√32
2^x(1+2+2^2+2^3)=15√32
2^x(1+2+4+8)=15√32
2^x(15)=15√32
2^x=√32
taking log on both side
log2^x=log√32
x log 2=1/2 log 32 use logm^n=nlogm
xlog 2=1/2 log 2^5
xlog2=5/2log2
x=5/2
2^x(1+2+2^2+2^3)=15√32
2^x(1+2+4+8)=15√32
2^x(15)=15√32
2^x=√32
taking log on both side
log2^x=log√32
x log 2=1/2 log 32 use logm^n=nlogm
xlog 2=1/2 log 2^5
xlog2=5/2log2
x=5/2
kaushikravikant:
thankyou Ration ji
Rational ji
thank u very much
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