Question

Find the value of x if 2 sinx=sqrt3​

Answer 1

Answer:

Consider the given equation.

√2(sinx+cosx)=3

(sinx+cosx)=23

 

On squaring both sides, we get

(sinx+cosx)2=23

sin2x+cos2x+2sinxcosx=23

 

We know that

sin2x+cos2x=1

sin2x=2sinxcosx

 

Therefore,

1+sin2x=23

sin2x=21

sin2x=sin6π

2x=nπ+(−1)n6π

x=2nπ+(−1)n12π

 

Hence, the value of x is 2nπ+(−1)n12π

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Answer 2

Answer:

Step-by-step explanation:

the value of sin x=root 3/2

by trigonometric table

sin 60 =root3/2

so the value of x=60