Find the value of x if 2 sinx=sqrt3
Answers
Answered by
7
Answer:
Consider the given equation.
√2(sinx+cosx)=3
(sinx+cosx)=23
On squaring both sides, we get
(sinx+cosx)2=23
sin2x+cos2x+2sinxcosx=23
We know that
sin2x+cos2x=1
sin2x=2sinxcosx
Therefore,
1+sin2x=23
sin2x=21
sin2x=sin6π
2x=nπ+(−1)n6π
x=2nπ+(−1)n12π
Hence, the value of x is 2nπ+(−1)n12π
it's a approved answers.
Answered by
1
Answer:
Step-by-step explanation:
the value of sin x=root 3/2
by trigonometric table
sin 60 =root3/2
so the value of x=60
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