Question

find the value of x if 2^x+2^x+2^x =192​

Answer 1

Answer:

x=6

Step-by-step explanation:

Given:

$2^x+2^x+2^x=192$

To Find:

Value of x

Procedure-

2^x+2^x+2^x=192

Since, $2^x$ is added 3 times, we can write

$3(2^x)=192$

$2^x=192/3$

$2^x=64$

64 can be written as 2*2*2*2*2*2, ie $2^6$

$2^x=2^6$

By law of Exponent-   $a^m=a^n$⇒$m=n$

Therefore,

x=6

Answer 2

Step-by-step explanation:

Answer:

x=6

Step-by-step explanation:

Given:

2^x+2^x+2^x=1922

x

+2

x

+2

x

=192

To Find:

Value of x

Procedure-

2^x+2^x+2^x=192

Since, 2^x2

x

is added 3 times, we can write

3(2^x)=1923(2

x

)=192

2^x=192/32

x

=192/3

2^x=642

x

=64

64 can be written as 2*2*2*2*2*2, ie 2^62

6

2^x=2^62

x

=2

6

By law of Exponent- a^m=a^na

m

=a

n

⇒m=nm=n

Therefore,

x=6