Question

Find the value of x,if√2+x +√3=√8.

Answer 1

Answer:

$\sqrt{2} + x + \sqrt{3} = \sqrt{8}$

$x = \sqrt{8} - \sqrt{2} - \sqrt{3}$

$x = \sqrt{ {2}^{3} } - \sqrt{2} - \sqrt{3}$

$x = \sqrt{2}( \sqrt{ {2}^{2} } - 1) - \sqrt{3}$

$x = \sqrt{2} - \sqrt{3}$

hope it helps

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