Question

find the value of x if 2 x , x + 0, 3x+2 are three consecutive terms A.P​

Answer 1

hope it help you...........

Answer 2

Answer:

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x= $\huge\frac{-2}{3}$

Step-by-step explanation:

$\huge\red{\underline\orange{\underline\purple{Given:}}}$

An A.P 2x, x+0, 3x+2..........which is of the form $a_1,a_2,a_3$

$\huge\red{\underline\orange{\underline\purple{To\: Find:}}}$

x value

$\huge\red{\underline\orange{\underline\purple{Explanation:}}}$

Common difference(d) can be written as $a_2-a_1$, which is also equal to $a_3-a_2$

So, x+0-2x=3x+2-(x+0)

x-2x= 3x+2-x

x-2x= 2x+2

-x-2x=2

-3x= 2

x= $\huge\frac{-2}{3}$

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