find the value of x if 24x=(72)²-(48)²
bhupesh99:
24x = 72×72 - 48×48 24x = 5184-2304 24x = 2880. x= 2880/24 = 120
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24x=(72)^2-(48)^2
24x=5184-2304
24x=2880
x=2880/24
x=120
24x=5184-2304
24x=2880
x=2880/24
x=120
Answered by
1
it is given that
24x=(72)^2-(48)^2
24x=(72+48)(72-48) (a^2+b^2=(a+b)(a-b) )
24x=120*24
24x=2880
x=2880/24=120.
therefore value of x will be 120.
if my answer is helpful for you then please mark as brain liest
24x=(72)^2-(48)^2
24x=(72+48)(72-48) (a^2+b^2=(a+b)(a-b) )
24x=120*24
24x=2880
x=2880/24=120.
therefore value of x will be 120.
if my answer is helpful for you then please mark as brain liest
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