Question

find the value of x if 25x÷2x=5√220.

Answer 1

am taking your question as,

25x2x = 220−−−√5Now, 25x÷ 2x = 25 × 25 × 25 × 25−−−−−−−−−−−−−−−−√5⇒ 25x − x = 2 × 2 × 2 × 2 [am ÷ an = am − n]⇒ 24x = 24⇒ 4x = 4⇒ x = 1

Answer 2

Correct -Question

Find the value of x if $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$.

Answer:

The value of x if $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$ is 1.

Step-by-step explanation:

Given:

Equation $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$.

To Find:

The value of x if $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$ .

Solution:

As given- equation $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$.

$2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$

$\frac{2^{5x} }{2^{x} } =(2^{20} )^{\frac{1}{5} }$

${2^{5x-x} = 2^{20\times\frac{1}{5} }$

$2^{4x} =2^{4}$

$4x=4$

$x=1$

Thus,the value of x if $2^{5x} \div2^{x} =\sqrt[5]{2^{20} }$ is 1.

PROJECT CODE #SPJ3