Find the value of X if ( 2X-3)^2- 6(X-4)-7=0
Answers
Step-by-step explanation:
Firstly this is an equation because you’re equating your value in Left Hand side (2X + 3) with your right hand side value (7).
Since we want to know the value of ‘X’, let that be on the left hand side and let all the numerical values come to the right. So, we will push ‘+3’ to right side and since we are switching sides, the sign gets reversed. In our case it is ‘+’ which would become ‘-’. Upon shifting the value to right, we get the following,
2X = 7 - 3 . (Here +3 became -3 once it came to right side)
2X = 4 (Simple subtraction)
Getting back to our primary goal, to push all the numbers in left side to right. When you push numbers from left to right, their actions do get changed. We saw how ‘+’ became ‘-’. Similarly,
Multiplication(*) on Left becomes division(/) on right and vice versa
In our equation, we have:
2 * X = 4 . (X is been multiplied by 2 on left, but when you push the number to right, action will be ‘division’. So value in the right side would be divided by 2)
We get,
X = 4/2
Upon solving we get,
X = 2.
Hope this helps! :)