find the value of x if (3÷5)^5(5÷3)^-9=(3÷5)^2x
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(3/5)^5 (5/3)^-9=(3/5)^2x ; (3/5)^5×(3/5)^9=(3/5)^2x ; (3/5)^14=(3/5)2x ;14=2x ;x=7
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(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power
(3÷5)^5+9 = (3÷5)^2x
5+9 =2x the base are same so, add the power
14 = 2x
x=14/2
x=7
(3÷5)^5+9 = (3÷5)^2x
5+9 =2x the base are same so, add the power
14 = 2x
x=14/2
x=7
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