Question

Find the value of X if (3/5)^x×(5/3)^2x=125/27

Answer 1

Step-by-step explanation:

we have to find the value of x if

(\frac{3}{5})^x\times (\frac{5}{3})^{2x}=\frac{125}{27}

The equation is

(\frac{3}{5})^x\times (\frac{5}{3})^{2x}=\frac{125}{27}

(\frac{5}{3})^{-x}\times (\frac{5}{3})^{2x}=\frac{125}{27}

(\frac{5}{3})^{x}=\frac{125}{27}

(\frac{5}{3})^{x}=(\frac{5}{3})^3

Comparing, we get

x=3

The value of x is 3 i.e x=3

Answer 2

Answer:

x=3

Step-by-step explanation:

(3/5)^× x (5/3)^2× =125/27

(3/5)^× x (3/5)^_2×=125/27

(3/5)^×_2× =125/27

(3/5)^_×=125/27

(5/3)^×=125/27

:. ×=3