Question

find the value of x if:-[(3/7) ³]-²=(3/7) ²^x​

Answer 1

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Answer 2

Showing results of

$\rm \Bigg [ \Bigg ( \dfrac{3}{7} \Bigg )^3 \Bigg ]^{-2} = \Bigg ( \dfrac{3}{7} \Bigg )^{2x}$

Solution:-

$\rm \implies \Bigg [ \Bigg ( \dfrac{3}{7} \Bigg )^3 \Bigg ]^{-2} = \Bigg ( \dfrac{3}{7} \Bigg )^{2x}$

$\rm\implies \Bigg ( \dfrac{3}{7} \Bigg )^{3(-2)} = \Bigg ( \dfrac{3}{7} \Bigg )^{2x} \qquad\qquad ...[ since, \ (a^m)^n = a^{mn}]$

$\rm \implies\Bigg ( \dfrac{3}{7} \Bigg )^{-6} = \Bigg ( \dfrac{3}{7} \Bigg )^{2x}$

Bases are same, so they will be eliminated.

$\rm\implies -6=2x$

$\rm\implies x = \dfrac{-6}{2} = -3$

$\bullet\qquad\bigstar\boxed{\bf x=-3}\bigstar$

Hope it helps..