Question

Find the value of x, if (3/8)^14 × (3/8)^(-9) = (3/8)^(2x-1)

Answer 1

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{\underline{\bf{\huge\mathcal{...Answer...}}}}$

$\underline{\large\mathcal\red{solution}}$

$( \frac{3}{8} ) {}^{14} \times (\frac{3}{8} ) {}^{ - 9} = ( \frac{3}{8} ) {}^{2x - 1} \\ >( \frac{3}{8} ) {}^{14 - 9} =( \frac{3}{8} ) {}^{2x - 1} \\ = > ( \frac{3}{8} ) {}^{5} = (\frac{3}{8} ) {}^{2x - 1} \\ = > 5 = 2x - 1 \\ = > 5 + 1 = 2x \\ = > x = \frac{6}{2} \\ = > x = 3$

$\large\mathcal\red{hope\: this \: helps \:you......}$