find the value of x if 3^x+64=2^6+root3^8
Answers
Answered by
1
Answer:
4
64 will cancel out.
for and positive integer .
By the logarithm, with the base 3
∴
Answered by
0
Answer:
3^x + 64 = 2^6 + √3^8
3^x + 64 = 64 + (√3^2)^4
Subtract 64 on both sides,
3^x + 64 - 64 = 64 - 64 + (√3^2)^4
3^x = (√3^2)^4
3^x = 3^4
Since, Base is same, therefore, the exponents will also be same.
Therefore, x = 4
Hope it helps you....
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