Question

find the value of x,if 30°c+300k+10k+xk=400°

Answer 1

Explanation:

given

30c+ 300k, 10k+xk=400k

covert them all into Kelvin k

(273+30) k +300k + 10k+ xk= 673k

613k + xk= 673k

xk= 673k- 613k

xk= 60k

X=60k

Answer 2

We consider 0°C equal to 273 K.

so, 30℃ = (30+273)K = 303 K

and, 400℃ = (400 + 273)K = 673K

now,

30°c+300k+10k+xk=400°c

=> 303 K + 300k + 10k + xk = 673k

=> xk = 673k - (303 K + 300k + 10k)

=> xk = 673k - 613k

=> xk = 60k

x = 60k (ans.)