Question

find the value of x if (4/15)^3 × (4/15)^-6
=(4/15)^2x+1​

Answer 1

Answer:

1

Step-by-step explanation:

LHS=(4/15)^3 × (4/15)^-6RHS=(4/15)^2x+1​

Lhs=(4/15)^(3 +(-6))

=> (4/15)^-3

If LHS=RHS

(4/15)^-3=(4/15)^2x+1

(As values are equal and the bases are equal so powers must be equal)

Hence bases are ommitted from both sides...

2x+1= -3

2x= -3-1

X= -4/2

X= -1

Ans value of x is 1

Why do all these bigs sum have their answers 1

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brainliest or atleast thank me✌✌

Answer 2

Answer:

the answer is (-2)

Step-by-step explanation:

$(\frac{4}{15})^{3} * (\frac{4}{15})^{-6} = (\frac{4}{15})^{2x+1}$ ------------------ (this is the question)

=> 3 + (-6) = 2x+1 -------------------------(∵$a^{m} * a^{n} = a^{m+n}$)

=> (-3) = 2x+1

=> (-3) - 1 = 2x -----------------------------(∵ moving like terms together)

=> (-4) = 2x

=>  $\frac{(-4)}{2}$ = x

=> (-2) = x -----------------(this is the answer)

∴the answer is (-2)

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