Question

Find the value of x if:
4^2x=1/32

Answer 1

Step-by-step explanation:

${4}^{2x} = \frac{1}{32 } \\ ({2}^{2} ) {}^{2x} = \frac{1}{ {2}^{5} } \\ {2}^{2 \times 2x} = (\frac{1}{2} )^{ 5} \\ {2}^{4x} = {2}^{ - 5}$

Comparing 2 in following

$4x = - 5 \\ x = \frac{ - 5}{4}$