find the value of x if (4/9)^4*(4/9)^-7=(4/9)^2x-3
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IF BASES ARE SAME THEN THE POWERS ARE ALSO SAME
SO ,
4+(-7) = 2x-1
4-7 = 2x-1
(-3) = 2x-1
2x = (-1)-(-3)
= (-1)+3
=(-2)
∴ x = (-2/2)
= (-1)
SO VALUE OF X IS (-1)
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