find the value of x if (5/6)^7 × (5/6)^-9=(5/6)^2x
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hi frnd
(5/6)^7×(5/6)^-9=(5/6)^2x
we know that a^m×a^n=a^m+n
so (5/6)^7+(-9)=(5/6)^2x
(5/6)^-2=(5/6)^2x
we know that when bases are equal powers should be equated
so -2=2x
x=-2/2
so x=-1
I believe this will help u ;)
(5/6)^7×(5/6)^-9=(5/6)^2x
we know that a^m×a^n=a^m+n
so (5/6)^7+(-9)=(5/6)^2x
(5/6)^-2=(5/6)^2x
we know that when bases are equal powers should be equated
so -2=2x
x=-2/2
so x=-1
I believe this will help u ;)
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