Find the value of x if 5^(x-3)(2x-3)=625 and answer is √11
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Answer:
Step-by-step explanation:
=> 5^(x-3)(2x-3) = 625
=> 5^[2x²-9x+9] = 625
=> 5^[2x²-9x+9] = 5⁴
by equalizing powers as their base is same...
=> 2x²-9x+9=4
=> 2x²-9x+5=0
=> D =b²-4ac =41
=> x= (-b±√D)/2a
=> x= { -(-9) ± √41 } /4
=> x= { 9 ± √41 } /4
=> x= { 9 ± 6.4... } /4
=> x= { 9 ± 6.4... } /4
=> x= 15.4.../4 or -3.4.../4
=> x= 3.84... or -0.85... and √11 = 3.6...
mark it brilliant ans. plz. it took me 15 to 20 min to type...
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