Find the value of x if ∠=50°, A B
∠=55° and AB ∥ CD
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Correct option is
A
20
It is given that AB∥CD and BC is transversal
from the figure we know that ∠BCD and ∠ABC are alternate interior angles
so we get
∠ABC=∠BCD
in order to find the value of x we can write it as
x
o
+∠ECD=70
o
....(i)
It is given that CD∥EF and CE is transversal
from the figure we know that ∠ECD and ∠CEF are consecutive interior angles
so we get
∠ECD+∠CEF=180
o
by substituting the values
∠ECD+130
o
=180
o
∠ECD=180
o
−130
o
∠ECD=50
o
Now by substituting ∠ECD in equation (i) we get
x
o
+∠ECD=70
o
x
o
+50
o
=70
o
x
o
=20
o
therfore the value of x is 20
o
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