find the value of x if (6/5) raised to the power x (5/6) raised to the power 2x = 125/216
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According to question-
[(6/5)^x]^2x = (125/216)
or (6/5)^2x² = (5³/6³) [ as 125 = 5³ and 216=6³]
or, (6/5)^2x² = (5/6)³ [as a^n/b^n = (a/b)^n]
or, 2x²= 3 [as if (a/b)^m = (a/b)^n , then m=n]
or, x² = 3/2
or, x = ✓(3/2)
[(6/5)^x]^2x = (125/216)
or (6/5)^2x² = (5³/6³) [ as 125 = 5³ and 216=6³]
or, (6/5)^2x² = (5/6)³ [as a^n/b^n = (a/b)^n]
or, 2x²= 3 [as if (a/b)^m = (a/b)^n , then m=n]
or, x² = 3/2
or, x = ✓(3/2)
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