find the value of x if (64/343) (343/64) ^ - x = (49/16) ^2x-1
Answers
Answered by
1
Answer:
solution:-
\begin{gathered} {( \frac{4}{7}) }^{ 3} \div {( \frac{343}{64}) }^{2x - 1} = \frac{16}{49} \\ {( \frac{4}{7} )}^{3} \times {( \frac{4}{7}) }^{6x - 3} = \frac{16}{49} \\ ( { \frac{4}{3} )}^{6x} = ( { \frac{4}{7}) }^{2} \\ 6x = 2 \\ x = \frac{2}{6} \\ x = \frac{1}{3} \end{gathered}
(
7
4
)
3
÷(
64
343
)
2x−1
=
49
16
(
7
4
)
3
×(
7
4
)
6x−3
=
49
16
(
3
4
)
6x
=(
7
4
)
2
6x=2
x=
6
2
x=
3
1
Answered by
5
Answer:
well the answer is -1/7
Step-by-step explanation:
here is the solution
(64/343)=(4/7)^3
same way (343/64)=(7/4)^3
so u can simplify ur expression as
(4/7)^3 x (7/4)^3 = (7/4)^4x-2
once u did this ,make the bases same
so u will get ur equation as
-3+(-3x)=4x-2
transfer the x and solve it u will get x=-1/7
hope u got ur answer
mark me the brainest
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